## Time and Work Test –

Time and Work – General Questions Placement Papers are logic and reasoning oriented tests and aims to shortlist candidates based on their **Time and Work Question** aptitude

### Time and Work

*Work from Days:*If A can do a piece of work in*n*days, then A’s 1 day’s work =1.*n**Days from Work:*If A’s 1 day’s work =1,then A can finish the work in*n*days.*n**Ratio:*If A is thrice as good a workman as B, then:Ratio of work done by A and B = 3 : 1.Ratio of times taken by A and B to finish a work = 1 : 3.

**Time And Work Tricks**

Time= Work done/Efficiency

**When work is same.**

** Time∝1/Efficiency**

**If A can do a piece of work in n days.**

** Then, per day working efficiency of A = 1/n**

**If working efficiency of A & B is → x : y.**

**Then, the time taken by A & B to finish the work is in the ratio → y : x**e.g. If A does three times faster work than ‘B’, then the ratio of work done by A and B is 3: 1.

Then, Ratio of time taken by A & B = 1 : 3

- If A can do a piece of work is x days and B can do a piece of work in y days, then both of them working together will do the same work in

**xy/(x+y) days**

**If A, B & C will working alone, can complete a work in x, y and z days, respectively, then they will together complete the work in**

**xyz/(xy+yz+zx)**

**Two persons A & B, working together, can complete a piece of work in x days. If A, working alone, can complete the work in y days, then B, working alone, will complete the work in**

**⇒xy/(y-x)**

**If A & B working together, can finish a piece of work is x days, B & C in y days, C & A in z days. Then, A + B + C working together will finish the job is**

**⇒2xyz/(xy+yz+zx)**

**If A can finish a work in x days and B is k times efficient than A, then the time taken by both A and B, working together to complete the work is**

**x/(1+k)**

**If A & B working together can finish a work in x days & B is k times efficient than A, then the time taken by,**

**A working Alone will take ⇒ (k + 1) x**

**B working Alone will take ⇒ ((k+1)/k)x**

**If A working Alone takes a days more than A & B, & B working Alone takes b days more than A & B. Then ,**

**Number of days, taken by A & B working together to finish a job is = √ab**