## Swinburne Test of DC Machine

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Swinburne Test of DC Machine – Swinburne’s test of DC shunt and compound wound DC machines is the straightforward and indirect technique for testing DC machines with constant flux. In honour of Sir James Swinburne, it is known as Swinburne’s test. With the aid of this test, the efficiency at any load with constant flux can be predicted. The ability to use the motor as a generator and measure no-load losses separately is Swinburne’s test’s key advantage. Because it uses no-load power input, this test is very straightforward and affordable. The Swinburne test of DC machines is discussed in this article.

## What is Swinburneâ€™s Test?

**Definition:** Swinburne’s test is an indirect test used to measure no-load losses separately and predict efficiency at any load in advance with constant flux on compound and shunt DC machines. This test is typically used to evaluate the efficiency, load losses, and temperature rise of large shunt DC machines. Another name for it is a load loss test or a no-load loss test.

### Swinburneâ€™s Test Theory

The circuit diagram of Swinburneâ€™s test is shown below. Consider that, the DC machine / DC motor runs at rated voltage with no-load input power. However, the speed of the motor can be regulated using the shunt regulator as shown in the figure. The no-load current and the shunt field current can be measured at the armatures A1 and A2. To find the armature copper losses, the resistance of the armature can be used.

Swinburneâ€™s test Circuit diagram

### Swinburne Test of DC Machine

The losses that occur in DC machines can be calculated with no load power using Swinburne’s test. Considering that all DC machines are is motors or generators. Only large shunt DC machines with constant flux are subject to this test. Finding out a machine’s efficiency in advance is very simple. This test is cost-effective because it uses a low input power when there is no load.

### Swinburne Test on DC Shunt Motor

To identify losses in a machine with no load, use the Swinburne’s test on a DC shunt motor. Armature copper losses, core iron losses, friction losses, and winding losses are the motors’ losses. Efficiency predicted and these losses are separately calculated. With no-load power input, the shunt motor’s output is zero, and this input no-load is used to supply the losses. Since the change in temperature rise cannot be measured at full load and the change in iron losses cannot be determined from no load to full load.

### Calculations

Swinburneâ€™s test calculations include calculation of efficiency at constant flux and losses of the DC machines. From the above circuit diagram, we can observe that the DC machine/DC shunt motorÂ runs at rated voltage with no-load. And the speed of the motor can controlled using the variable shunt regulator.

#### At no-Load

Consider, the no-load current is â€˜Ioâ€™ at armature A1

Shunt field current measured at Armature A2 is â€˜Ishâ€™

The no-load armatures current is the difference between no-load current and shunt field current at A2, given as = (Io â€“ Ish

The input power at no-load in watts = VIo

The equation for armature copper losses at no-load power input is, = ( Io â€“ Ish ) ^2 Ra

Here Ra is the resistance of the armature.

The constant losses at no-load are the subtraction of armature copper losses from the no-load input power.

Constant losses C = V Io â€“ ( Io â€“ Ish )^2 Ra

#### At Load

The efficiency of the DC machine/ DC shunt motor at any load can be calculated.

Consider the load current I, to determine the efficiency of the machine at any load.

When the DC machine acts as a motor, the armature current Ia = ( Io â€“ Ish )

When the DC machine acts as a generator, the armature current Ia = ( Io + Ish )

Input power = VI

For DC motor at on load:

Armature copper losses are Pcu = I^2 Ra

Pcu = ( I â€“ Ish )^2 Ra

Constant losses C = VIo â€“ ( Io â€“ Ish )^2 Ra

Total losses of the DC motor = armature copper losses + constant losses

Total losses = Pcu + C

Hence the efficiency of the DC motor at any load is, Nm = output/input

Nm = ( input â€“ losses ) / input

Nm = ( VI â€“ ( Pcu + C ) ) / VI

### For DC Generator on Load

Input power at no-load = VI

Armature copper losses = Pcu = I^2 Ra

Pcu = ( I + Ish )^2 Ra

Constant losses C = VIo â€“ ( I â€“ Ish )^2 Ra

Total losses = armature copper losses Pcu + Constant losses C

Hence the efficiency of the DC machine when it acts as a generator at any load is

Ng = output / input

And Ng = ( input â€“ losses )/ input

Ng = ( VI â€“ ( Pcu + C ) / VI

These are the equations for no-load losses and the efficiency of the DC machines at any load.

### Swinburneâ€™s Test Applications

The applications of swinburne test include the following.

- This test is used to find efficiency and no-load losses of the DC machines at constant flux.
- In DC machines when runs as motors
- In DC machines when runs as generators
- In large shunt DC motors.

### Swinburneâ€™s Test Advantages & Disadvantages

The advantages of swinburne test include the following.

- This test is very simple, economical and most commonly used
- It requires no-load power input or less power input when compared to Hopkinsonâ€™s test.
- Efficiency can be determined in advance because of the known constant losses.

The disadvantages of swinburne test include the following.

- The change in iron losses from no-load to full-load cannot be determined because of the armature reaction
- It is not applicable for DC series motors
- Commutation conditions and temperature rise cannot be checked at full-load with the rated voltage.
- It is applicable for the DC machines which have constant flux.

So In other words, this is all about the Swinburne test, including its definition, theory, circuit diagram, application to DC machines and DC shunt motors, test calculations, benefits, drawbacks, and distinction from Hopkinson’s test.